patiencehope7
patiencehope7 patiencehope7
  • 15-05-2020
  • Mathematics
contestada

[tex]\sqrt{28}=\sqrt{a^{2} }[/tex]

solve for a

Respuesta :

jimrgrant1 jimrgrant1
  • 15-05-2020

Answer:

a = 2[tex]\sqrt{7}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{28}[/tex] = [tex]\sqrt{a^{2} }[/tex], then

a² = 28 ( take the square root of both sides )

a = [tex]\sqrt{28}[/tex] = [tex]\sqrt{4(7)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{7}[/tex] = 2[tex]\sqrt{7}[/tex]

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