Danielle819
Danielle819 Danielle819
  • 13-06-2020
  • Mathematics
contestada

Make r the subject of the formula 
v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h​) 
​

Respuesta :

Cathenna
Cathenna Cathenna
  • 13-06-2020

Answer:

[tex] \boxed{r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } } [/tex]

Step-by-step explanation:

[tex]Solve \: for \: r: \\ = > v= \pi {h}^{2}(r - \frac{h}{3} ) \\ \\ v=\pi {h}^{2}(r - \frac{h}{3} )is \: equivalent \: to \: {h}^{2}\pi(r - \frac{h}{3} ) = v: \\ = > {h}^{2}\pi(r - \frac{h}{3} ) = v \\ \\ Divide \: both \: sides \: by \: \pi {h}^{2} : \\ = > r - \frac{h}{3} = \frac{v}{\pi {h}^{2} } \\ \\ Add \: \frac{h}{3} \: to \: both \: sides: \\ = > r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } [/tex]

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