Answer:
[tex]x=i\sqrt{2} -1, x=-i\sqrt{2}-1[/tex]
Step-by-step explanation:
Hoping the equation is [tex]x^2+2x+3 = 0[/tex]
Rewrite so I can complete the square:
[tex]x^2+2x=-3[/tex]
Take the square of half of 2 and square.
[tex]x^2+2x+1=-2[/tex]
[tex](x+1)^2=-2[/tex]
[tex]x + 1=\sqrt{-2}[/tex]
[tex]x=i\sqrt{2} -1, x=-i\sqrt{2}-1[/tex]
