Answer:
2nd option is the correct answer.
[tex] 5\frac{1}{3}\: units[/tex]
Step-by-step explanation:
[tex] In\:\triangle XWZ, \: \angle XWZ= 90°
\\ \: \&\: WY \perp XZ\\[/tex]
Therefore, by geometric mean postulate:
[tex] WY^2 = XY\times YZ\\
\therefore 4^2 = 3\times a\\
\therefore 16 = 3a
\therefore a = \frac{16}{3}\\\\
\huge \red {\boxed {\therefore a = 5\frac{1}{3}\: units}} [/tex]
