xiaotongexiongp53gk1
xiaotongexiongp53gk1 xiaotongexiongp53gk1
  • 15-07-2020
  • Mathematics
contestada

What is the smallest positive integer n for which [tex]n^{2}[/tex] is divisible by 18 and [tex]n^{3}[/tex] is divisible by 640?

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sqdancefan
sqdancefan sqdancefan
  • 19-07-2020

Answer:

  120

Step-by-step explanation:

n^2 has a factor of 18, so factors of 3^2·2. Since n^2 is a perfect square, we know n must have a factor of 3·2 = 6.

n^3 has a factor of 640, so factors of 2^7·5. Since n^3 is a perfect cube, we know n must have a factor of 2^3·5 = 40.

The least common multiple of 6 and 40 is 120.

The smallest positive integer n is 120.

_____

Check

120^2/18 = 800

120^3/640 = 2700

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