Given that,
ABC and ADC are triangles.
The area of ΔADC is 52 m².
Suppose , AD is the median.
According to figure,
We need to find the area of ΔABC
Using theorem of triangle
[tex]\bigtriangleup ADB +\bigtriangleup ADC=\bigtriangleup ABC[/tex]
Here, Δ ADB = Δ ADC
So, [tex]2 \bigtriangleup ADC=\bigtriangleup ABC[/tex]
Put the value of Δ ADC
[tex]\bigtriangleup ABC =2\times52[/tex]
[tex]\bigtriangleup ABC = 104\ m^2[/tex]
Hence, The area of ΔABC is 104 m².
