Answer:
Step-by-step explanation:
Hello, please consider the following.
We need to factorise as much as possible and eliminate the same term from numerator and denominator
[tex]\dfrac{\dfrac{x^2-4x-5}{x-2}}{\dfrac{2x-10}{x^2-4}}\\\\\\=\dfrac{(x^2-4x-5)}{(x-2)}\dfrac{(x-2)(x+2)}{(2x-10)}\\\\\\=\dfrac{(x-5)(x+1)(x+2)}{(2x-10)}\\\\\\\large \boxed{=\dfrac{(x+1)(x+2)}{2}}[/tex]
Thank you
