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12-09-2016
Chemistry

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how many moles of naoh are present in 29.0 ml of 0.290 m naoh?

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Willchemistry Willchemistry

13-09-2016

29.0 mL in liters:

29.0 / 1000 => 0.029 L

n = M x V

n = 0.290 x 0.029

n = 0.00841 moles of NaOH

hope this helps!

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