the length of each side of a square is 3 inches more than the length of each side of a smaller square. The sum of the areas of the squares is 149^2. Find the lengths of the sides of the two squares
The length of each side of a square is 3in more than the length of each side of a smaller square. let the length of smaller square=x the length of big square=x+3 The sum of the areas of the squares is 149in^2. so x^2+(x+3)^2=149 or x^2+x^2+6x+9=149 or 2x^2+6x=149-9=140
