Answer:
[tex]\sqrt{35}[/tex]
Step-by-step explanation:
h =-19
j =16
[tex]\sqrt{j-h} = ?[/tex]
Substitute values into the given equation
[tex]\sqrt{16-(-19)} \\\\\mathrm{Apply\:rule}\:-\left(-a\right)=a\\\\=\sqrt{16+19}\\\\\mathrm{Add\:the\:numbers:}\:16+19=35\\\\=\sqrt{35}[/tex]
