Let , radius of sphere 1 is r .
So , radius of sphere 2 is 6r .
Surface area of sphere is given by :
[tex]A=4\pi r^2[/tex]
So ,
[tex]\dfrac{A_2}{A_1}=\dfrac{4\pi(6r)^2}{4\pi r^2}\\\\\dfrac{A_2}{A_1}=36[/tex]
Volume is given by :
[tex]V=\dfrac{4}{3}\pi r^3[/tex]
Ratio of sphere 2 by sphere 1 is given by :
[tex]\dfrac{V_2}{V_1}=\dfrac{\dfrac{4}{3}\pi (6r)^3}{\dfrac{4}{3}\pi r^3}\\\\\dfrac{V_2}{V_1}=216[/tex]
Therefore , the ratio of area and volume is 36 and 216 respectively .
Hence , this is the required solution .
