andrewperry31705 andrewperry31705

12-10-2020
Mathematics

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the lager of two numbers is 10 less than twice the smaller number if te sum of the two is 38 find the largest number

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nineex5 nineex5

12-10-2020

Answer:

22

Step-by-step explanation:

a=larger number b= smaller number

a=2b-10, a+b=38

2b-10+b=38

3b=48

3b/3=48/3

b=16

a+16=38

a=38-16

a=22

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