Answer:
[tex]first \: \\ x {}^{2} + x \\ = x(x + 1) \\ \\ second \\ {x}^{2} - 1 \\ = (x) {}^{2} - (1) { }^{2} \\ = (x + 1)(x - 1) \\ \\ third \\ x {}^{2} - x \\ = x(x - 1) \\ \\ therefore \: \: lcm = x(x + 1)(x - 1)[/tex]
Thank you ☺️☺️
