Answer:
[tex]a_{n}[/tex] = 3[tex](2)^{n-1}[/tex]
Step-by-step explanation:
There is a common ratio r between consecutive terms in the sequence, that is
6 ÷ 3 = 12 ÷ 6 = 24 ÷ 12 = 48 ÷ 24 = 2
This indicates the sequence is geometric with n th term
[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 3 and r = 2 , thus
[tex]a_{n}[/tex] = 3[tex](2)^{n-1}[/tex]
