Answer:
0.088 M.
Explanation:
Assuming that the temperature is 429 K, we can calculate the concentration of NO₂. Kc(429K) = 0.490.
The reaction is:
N₂O₄(g) ⇄ 2NO₂(g)
0.04 0.04
0.04 - x 0.04 + 2x
The constant of the reaction is:
[tex] Kc = \frac{[NO_{2}]^{2}}{[N_{2}O_{4}]]} [/tex]
[tex] 0.490 = \frac{(0.04 + 2x)^{2}}{0.04 - x} [/tex]
[tex] 0.490*(0.04 - x) - (0.04 + 2x)^{2} = 0 [/tex]
By solving the above equation for x we have:
x = 0.024 = [NO₂]
Hence the concentration of NO₂ is:
[tex] [NO_{2}] = 0.04 + 2*0.024 = 0.088 M [/tex]
I hope it helps you!
