Answer:
The magnitude of acceleration of the student is 0.6 m/s²
Explanation:
Given that,
Initial velocity = 2.8 m/s
Final velocity = 4.7 m/s
Time = 3.4 sec
We need to calculate the magnitude of acceleration of the student
Using formula of acceleration
[tex]a=\dfrac{v_{f}-v_{i}}{t}[/tex]
Where, [tex]v_{f}[/tex] = final velocity
[tex]v_{f}[/tex] = final velocity
t = time
Put the value into the formula
[tex]a=\dfrac{4.7-2.8}{3.4}[/tex]
[tex]a=0.6\ m/s^2[/tex]
Hence, The magnitude of acceleration of the student is 0.6 m/s²
