Answer:
[tex]-\frac{1}{2}[/tex]
Diverging lens
Explanation:
Given parameters:
Power of lens = -2.0D
Unknown:
Focal length = ?
Solution:
The power of lens is the reciprocal of the focal length;
P = [tex]\frac{1}{f}[/tex]
where f is the focal length
f = [tex]\frac{1}{P}[/tex] = [tex]-\frac{1}{2}[/tex]
The lens is a diverging lens
