Answer:
y(2x+3y-6)
Step-by-step explanation:
2xy+ [tex]3y^{2}[/tex]-6y
Find the H.C.F
2xy= 2×x×y
3y²= 3×y×y
6y= 6×y
H.C.F= y
2xy÷y+ 3y²÷y- 6y÷y
= 2x+ 3y- 6
= y( 2x+ 3y-6)
