aieshahamid7 aieshahamid7
  • 13-11-2020
  • Mathematics
contestada

4. X varies directly with the square of y, where x>0,
and y >0. If x= 3 when y = 5, then what is the value
ofy when x= 48?

Respuesta :

oeerivona oeerivona
  • 18-11-2020

Answer:

The value of y, when x = 48 is y = 12/5

Step-by-step explanation:

The given parameters are;

x is directly proportional to y

Where x > 0, y > 0

For x = 3. y = 5

Therefore, we have;

x ∝ a·y²

For ,x = 3, when y = 5, we have;

3 = a × 5² = 25·a

∴ a = 25/3

When x = 48, we have;

48 = 25/3×y²

y² = 3/25 × 48 = 144/25

y = √(144/25) = 12/5

y = 12/5

The value of y, when x = 48 is y = 12/5.

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