V2iderabrookeyda V2iderabrookeyda

13-10-2016
Mathematics

contestada

Solve the equation!3 tan^3θ = tan θ

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HomertheGenius HomertheGenius

25-10-2016

3 tan³ t(theta) = tan t(theta)
3 tan³ t - tan t = 0
tan t ( 3 tan² t - 1 ) = 0
tan t = 0
t 1 = k π , k ∈ Z
3 tan ² t - 1 = 0
3 tan ² t = 1
tan ² t = 1/3
tan t = +/- √3/3
t 2 = π / 6 + k π
t 3 = - π / 6 + k π , k ∈ Z

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