8x + 6y = 28
9x + 3y = 39
to first solve the system, we need to isolate one variable. we will solve for x first so we need to cancel out the y. to do this, we will multiply the second equation by -3
8x + 6y = 28
(9x + 3y = 39) -2
8x + 6y = 28
-18x -6y = -78
now combine
-10x = -50
divide by -10
x=5
now we plug x back into the equation to solve for y
8(5)+6y = 28
40 + 6y = 28
6y= -12
y= -2
