Given that,
AD is parallel to EC, BD is congruent to BC.
Solution,
Here,
[tex]\angle D=\angle C[/tex] = the reason for this is that the two angles are alternate interior angle. So, by alternate interior angle theorem [tex]\angle D=\angle C[/tex].
As [tex]\angle ABD=\angle EBC[/tex] = due to vertically opposite theorem
It means,
[tex]\triangle ABD \cong \triangle EBC[/tex] (angle-side-angle)
Hence, the correct option is (c).
