iitzdawnn79
iitzdawnn79 iitzdawnn79
  • 14-12-2020
  • Mathematics
contestada

Determine the value of k so that f(x)=x^3+kx^2-kx-93 is divisible by (x+3) with no remainder​

Respuesta :

AFOKE88 AFOKE88
  • 19-12-2020

Answer:

k = 10

Step-by-step explanation:

For f(x) = x³ + kx² - kx - 93 to be divisible by (x+3) with no remainder, it means that at (x + 3) is a factor of the polynomial f(x).

Thus, it means that at x = -3, f(x) must be equal to zero.

Thus;

(-3)³ + k(-3)² - k(-3) - 93 = 0

-27 + 9k + 3k - 93 = 0

12k - 120 = 0

12k = 120

k = 120/12

k = 10

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