Ian1037
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Give the equation of a line that is perpendicular to
f(x)= 3x+1 and goes through the point (0, -6).

Respuesta :

Answer: -1/3x - 6

Step-by-step explanation: perpendicular lines have opposite reciprocal slopes

original slope of 3 —-> -1/3

then our point is (0, -6) let’s plug that into y=-1/3x+b

-6 = -1/3(0)+b

b= -6

put it all together: y = -1/3x -6

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