Answer:
or, x2-(2-15)x +30= 0
or, x2-2x-15x + 30= 0
or,x(x-2)-15(x-2)=0
or, (x-2) (x-15)=0
either, or,
x-2=0 x-15=0
x2-(10+3)x+30=0
x2-10x-3x+30=0
x(x-10)-3(x-10)=0
(x-10)(x-3)=0
x-10=0 x-3=0
x=10 x=3
therefore,x=10,3
