Given:
Two similar rectangles.
To find:
The area of the larger rectangle.
Solution:
Let x be the other side of the larger rectangle.
Corresponding sides of similar figures are always congruent.
[tex]\dfrac{x}{1}=\dfrac{4}{2}[/tex]
[tex]x=2[/tex]
The other side of larger rectangle is 2 cm.
We know that, area of rectangle is
[tex]Area=Length\times Width[/tex]
So, area of the larger rectangle is
[tex]Area=4\times 2[/tex]
[tex]Area=8[/tex]
Therefore, the area of the larger rectangle is 8 sq. cm.
