DrAngelaZiegler DrAngelaZiegler
  • 13-01-2021
  • Advanced Placement (AP)
contestada

The one-to-one functions g and h are defined as follows.
g={(-9,-4),(-7,3),(0,-6),(8,0)
h(x)=4x+9

I need to know what g^-1(0) is. I need help!

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 18-01-2021

Answer:

[tex]g^{-1}(0) = 8[/tex]

Explanation:

Given

[tex]g=\{(-9,-4),(-7,3),(0,-6),(8,0)\}[/tex]

[tex]h(x) = 4x + 9[/tex]

Required

Find [tex]g^{-1}(0)[/tex]

A relation is represented as: [tex](x,y)[/tex]

And the following relationships exist between x and y

[tex]y = g(x)[/tex]

and

[tex]x =g^{-1}(y)[/tex]

So: [tex]g^{-1}(0)[/tex] implies that:

[tex]x = g^{-1}(0)[/tex]

Which means that: we look for the corresponding value of x where y = 0.

Hence:

[tex]x = g^{-1}(0) = 8[/tex]

[tex]g^{-1}(0) = 8[/tex]

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