Step-by-step explanation:
I don't know if you are asking for a solution using the method of completing the squares.
3x²-2x-5=0
x²-⅔x-5/3=0
x²-⅔x=5/3
x²-⅔x+(-⅓)²=5/3+(-⅓)²
(x-⅓)²=5/3+1/9
(x-⅓)²=16/9
(x-⅓)²=√16/9
x-⅓=±4/3
x=⅓±4/3
x=5/3,-1
Thus (3x-5)(x+1)
