Answer:
[tex]\frac{x+3}{x+2}[/tex]
Step-by-step explanation:
[tex]\frac{x^2+10x+21}{x^2+9x+14}[/tex] Factor the expressions that are not already factored.
=
[tex]\frac{(x+3)(x+7)}{(x+2)(x+7)}[/tex] Cancel out x+7 in both numerator and denominator.
=
[tex]\frac{x+3}{x+2}[/tex]
