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15-02-2021
Chemistry

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3- Given 90.0 g C6H1206
a- How many moles of Glucose are present in 90.0 g of glucose?

Respuesta :

15-02-2021

molar mass = 180.18

//

[tex]90.0 \: g \times \frac{1 \: mol}{180.18 \: g} = 0.4995004995 \: mol[/tex]

[tex] = 0.500 \: mol[/tex]

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