sugakookiemyship sugakookiemyship
  • 15-02-2021
  • Mathematics
contestada

Line segment JK has endpoints at J(-3,4) and K(3,6). Which is an equation of a line that is perpendicular to line segment JK and passes through the point (3,-12)

Respuesta :

cwrw238 cwrw238
  • 15-02-2021

Answer:

y = -3x - 3.

Step-by-step explanation:

Find the slope of the line JK:

Slope = (6-4)/(3- (-3))

= 2 / 6

= 1/3.

Therefore the slope of the line perpendicular to it is - 1 / 1/3

= -3.

Now we use the point-slope form of a line to get the required equation:

y - y1 = m(x - x1)

Here m = -3 and (x1, y1) = (3, -12) so we have

y - (-12) = -3(x - 3)

y + 12 = -3x + 9

y = -3x + 9 - 12

y = -3x - 3 is the answer.

Answer Link

Otras preguntas

Find the value of x that makes ABCD a parallelogram. А. х = 50° в. х = 10" с. х = 40° D. х = 30°
which is worse? a mutation at the beginning of a gene or the end of a gene?
Explain how protective factors can offset risks?
Things you can see and touch are referred to as?
5892 \ 18 = what is the answer To this question
Today, a man on television described his experience of _____, a condition in which the senses become joined. He explained that when certain types of music are p
A 3600 kg truck is parked on a 14 ∘ slope. You may want to review (Pages 141 - 145) . Part A How big is the friction force on the truck? The coefficient of stat
Given a = -3 and b= 4 and c=-5, evaluate lc - a - bl. 4 2 6
What is the name of the tribe that built temples for their God's?
What is the role of a United States attorney?