mirzamumtaz609 mirzamumtaz609
  • 16-02-2021
  • Mathematics
contestada

Find the value of expression - 17x-19xpwer4 - 21x power 2,when x=3

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Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 21-02-2021

Answer:

[tex]-17x - 19x^4 - 21x^2 = -1779[/tex] when [tex]x = 3[/tex]

Step-by-step explanation:

Given

[tex]-17x - 19x^4 - 21x^2[/tex]

[tex]x = 3[/tex]

Required

Solve

Substitute 3 for x in [tex]-17x - 19x^4 - 21x^2[/tex]

[tex]-17x - 19x^4 - 21x^2 = -17*3 - 19*3^4 - 21*3^2[/tex]

Evaluate all exponents

[tex]-17x - 19x^4 - 21x^2 = -17*3 - 19*81 - 21*9[/tex]

[tex]-17x - 19x^4 - 21x^2 = -51 - 1539- 189[/tex]

[tex]-17x - 19x^4 - 21x^2 = -1779[/tex]

Answer Link

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