Respuesta :
Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the centre and r is the radius.
(x + 1.5)^2 + (y + 1)^2 = 9
(x - (-1.5))^2 + (y - (-1))^2 = 3^2
Center = (-1.5, -1) and radius is 3.
(x + 1.5)^2 + (y + 1)^2 = 9
(x - (-1.5))^2 + (y - (-1))^2 = 3^2
Center = (-1.5, -1) and radius is 3.
we know that
The equation of the circle is of the form
[tex] (x-h)^{2} +(y-k)^{2} =r^{2} [/tex]
where
[tex] (h,k) [/tex] is the center
[tex] r [/tex] is the radius
in this problem
we have
[tex] (x+1.5)^{2} +(y+1)^{2} =9 [/tex]
[tex] (x+1.5)^{2} +(y+1)^{2}=3^{2} [/tex]
So
the center is the point [tex] (-1.5,-1) [/tex]
the radius is [tex] 3 [/tex] units
using a graph tool
see the attached figure
