Answer:
x = 1 and x = 7
Step-by-step explanation:
The given equation is [tex]x^2 - 8x + 7 = 0[/tex].
We need to solve the equation.
It is a quadratic equation whose solution is given by :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
Here, a = 1, b = -8 and c = 7
Put values,
[tex]x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(1)(7)} }{2(1)}\\\\=\dfrac{8\pm \sqrt{64-28}}{2}\\\\=\dfrac{8\pm 6}{2}\\\\=\dfrac{8+6}{2},\dfrac{8-6}{2}\\\\=7,1[/tex]
So, the values of x are x = 1 and x = 7.
