Answer: The volume occupied by He is 62.4 L
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 0.980 atm
V = Volume of gas = ?
n = number of moles = 2.50 mol
R = gas constant =
T =temperature =[tex]25.0^0C=(25.0+273)K=298.0K[/tex]
[tex]V=\frac{nRT}{P}[/tex]
[tex]V=\frac{2.50mol\times 0.0821 Latm/K mol\times 298.0K}{0.980atm}=62.4L[/tex]
Thus the volume occupied by He is 62.4 L
