Step-by-step explanation:
We are given two Triangles and we need to prove them congruent . In ∆AOC and ∆BOD , we have
[tex]\to AC = BD ( given ) \\\\\to OD = OA \\\\\to \angle CAO =\angle BDO (Since\ BD || AC ) [/tex]
Therefore by AAS congruent condition we can say that ,
[tex]\implies\red{ \triangle AOC \cong \triangle BOD }[/tex]
Hence Proved!
