Given:
The equation is:
[tex]\dfrac{7}{3}+x=3[/tex]
To find:
The value of x.
Solution:
We have,
[tex]\dfrac{7}{3}+x=3[/tex]
Subtract both sides by [tex]\dfrac{7}{3}[/tex].
[tex]\dfrac{7}{3}+x-\dfrac{7}{3}=3-\dfrac{7}{3}[/tex]
[tex]x=\dfrac{9-7}{3}[/tex]
[tex]x=\dfrac{2}{3}[/tex]
Therefore, the value of x is [tex]\dfrac{2}{3}[/tex] or it can be written as 0.667.
