Answer:
[tex]-\frac{15}{2}[/tex]
Step-by-step explanation:
[tex]\mathrm{Subtract\:}135\mathrm{\:from\:both\:sides}[/tex]
[tex]4x^2+12x-135=135-135[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]4x^2+12x-135=0[/tex]
[tex]x1, 2=−b±√b2−4ac2a For a=4, b=12, c=−135x1, 2=−12±√122−4· 4(−135)2· 4[/tex]
