Respuesta :

shihabmollah615

Answer:

Given series is 9

1/3

×9

1/9

×9

1/27

×.....∞

=9

(

3

1

+

9

1

+

27

1

+....∞)

=9

(1−r)

a

, where a=

3

1

and r=

3

1

=9

(1−

3

1

)

(1/3)

=9

2

1

=

9

=3.

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