Answer:
4.02×10⁻⁴ K⁻¹
Explanation:
Applying,
γ = (v₂-v₁)/(v₁Δt)................. Equation 1
Where γ = coefficient of volume expansion, v₂ = Final volume, v₁ = initial volume, Δt = change in temperature.
From the question,
Given: v₂ = 850 m³, v₁ = 830 m³, Δt = (90-30) = 60°C
Substitute these values into equation 1
γ = (850-830)/(830×60)
γ = 20/(830×60)
γ = 4.02×10⁻⁴ K⁻¹
