Answer:
DE ║ BC
BC = 2(DE)
Step-by-step explanation:
From the picture attached,
AD = DB [Given]
AE = EC [Given]
Therefore, points D and E will be the midpoints of the sides AB and AC.
By midsegment theorem,
Segment joining midpoints of the two sides of a triangle is parallel and measures the half of the third side of the triangle.
DE ║ BC
DE = [tex]\frac{1}{2}(BC)[/tex]
BC = 2(DE)
