Answer:
Forth term = x + 6
Fifth term = x + 8
Sixth term = x + 10
Formular for nth term:
[tex]{ \tt{n _{th} = a + (n - 1)d}} \\ { \tt{{n _{th} = x + (n - 1) \times 2}}} \\ { \tt{{n _{th} =x + 2n - 2 }}}[/tex]
Answer:
Hello,
Step-by-step explanation:
First term of this aritmetical sequence is x+0*2
[tex]U_1=x+0*2\\U_2=x+2=x+1*2\\U_3=x+4=x+2*2\\U_4=x+6=x+3*2\\\\n^{th}\ term\ is\ U_n=x+(n-1)*2\\[/tex]
