Answer:
[tex]W= 208 KJ[/tex]
Explanation:
From the question we are told that:
Take in Temperature [tex]T_1=400C=>673K[/tex]
Take Out Temperature [tex]T_2=120+>393K[/tex]
Heat [tex]Q=500kJ[/tex]
Generally the equation for Carnot Engine Efficiency is mathematically given by
[tex]n_c=\frac{T_1-T_2}{T_1}[/tex]
[tex]n_c=\frac{673-393}{673}[/tex]
[tex]n_c=0.4[/tex]
Where
[tex]n_c=\frac{W}{Q}[/tex]
[tex]W = Q*n_c[/tex]
[tex]W= 500 * 0.4[/tex]
[tex]W= 208 KJ[/tex]
