Answer:
[tex]P'(x)=2.2-0.12x[/tex]
Step-by-step explanation:
start by finding [tex]P(x) = R(x)-C(x)[/tex]
[tex]P(x)=3x-0.06x^2-286-0.8x[/tex]
to find P'(x), you take the derivative of P(x)
[tex]P'(x)=\frac{d}{dx} (2.2x-286-0.06x^2)[/tex]
[tex]\frac{d}{dx} (2.2x-286-0.06x^2)=2.2-0.12x[/tex]
so [tex]P'(x)=2.2-0.12x[/tex]
