christiandsoriano christiandsoriano

15-08-2021
Mathematics

contestada

11. The rectangle has a width of 8 in, a length of x-5 in, and an area of 16 in. Solve for X.
Hint: label the figure.
K-5in
8in

11 The rectangle has a width of 8 in a length of x5 in and an area of 16 in Solve for X Hint label the figure K5in 8in class=

Respuesta :

ghaithgh ghaithgh

15-08-2021

Area = width × length

16= 8 × (X –5 )

16 = 8X – 40

8X = 16 + 40

8X = 56

X= 56 / 8

X= 7 in

I hope I helped you^_^

Answer Link

anasweeney43 anasweeney43

15-08-2021

Answer: x =

Step-by-step explanation:

Area = width times length

8*(x-5)=16

8x - 40 = 16

8x = 16 + 40

x = 56/8

x = 7

Answer Link

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