Answer:
[tex] {6y}^{2} [/tex]
Step-by-step explanation:
Given,
[tex] \frac{1}{ {6y}^{ - 2} } [/tex]
Since,
[tex] {x}^{ab} = {( {x}^{a} )}^{b} [/tex]
Hence,
[tex] = \frac{1}{ {( {6y}^{2} )}^{ - 1} } [/tex]
Since,
[tex] \frac{1}{ {x}^{ - 1} } = x[/tex]
Hence,
[tex] = {6y}^{2} (ans)[/tex]
