Respuesta :
The general parabola equation
[tex]ax^{2} +bx+c=0[/tex]
in this equation
[tex]y=x^{2} -16[/tex] you have
a=1 b=0 and c=-16
[tex]xv=\frac{b}{2a} =-\frac{0}{2} =0[/tex]
[tex]yv=(0)^{2} -16=-16[/tex]
the vertex is (0,-16)
graph{y=x^2-16 [-26.2, 25.1, -19.67, 6]}
Answer:
Step-by-step explanation:
in this equation
you have
a=1 b=0 and c=-16
the vertex is (0,-16)
graph{y=x^2-16 [-26.2, 25.1, -19.67, 6]}
