lucillekay
lucillekay lucillekay
  • 11-11-2021
  • Mathematics
contestada

If the perimeter of a rectangle is 6x^2-2x+14 and the length is x^2-x+8 what is the measure of the width?

Please help!!

Respuesta :

jlim1005 jlim1005
  • 11-11-2021

Answer:

w = 2x^2-2x+15

Step-by-step explanation:

Since the formula to find the perimeter is P=2l+2w, use this to set up your equation:

6x^2-2x+14 = 2(x^2-x+8) + 2w

Then, distribute the 2 to everything inside the parentheses.

6x^2-2x+14 = 2x^2-2x+16 + 2w

Subtract 2x^2-2x+16 from both sides, leaving you:

4x^2-4x+30 = 2w

Divide 2 from both sides.

2x^2-2x+15

The answer is 2x^2-2x+15

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