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ASAP
A train is travelling at 100 m/s when it receives an alert: “Brake! 600 meters ahead, the rails are broken”. The highest acceleration that the train can produce is 10 m/s^2. If the train slows down with a constant acceleration of 10 m/s^2
How long will it take for the train to stop?
How many meters will it travel before it stops?
Botcookiemaster please don't use a file just give me the answer

Respuesta :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's consider the given terms ~

  • Initial velocity (u) = 100 m/s

  • Acceleration (a) = - 10 m/s²

(Acceleration is negative bbecause train slows down)

  • Final velocity (v) = 0 m/s

(final velocity is 0, because train stops)

Now, let's find the time taken (t) by using the first equation of motion ~

  • [tex]v = u + at[/tex]

  • [tex]0 = 100 + ( - 10 \times t)[/tex]

  • [tex]0 = 100 - 10t[/tex]

  • [tex]10t = 100[/tex]

  • [tex]t = 100 \div 10[/tex]

  • [tex]t = 10[/tex]

The train will take 10 secs to stop,

Now, let's find how much distance (s) it will cover before it stops using second equation of motion ~

  • [tex]s = ut + \dfrac{1}{2} at {}^{2} [/tex]

  • [tex]s = (100 \times 10) + ( \dfrac{1}{ 2} \times - 10 \times 10 \times 10)[/tex]

  • [tex]s = 1000 + ( - 500)[/tex]

  • [tex]s = 1000 - 500[/tex]

  • [tex]500 \: \: m[/tex]

It will cover 500 meters before coming to rest ~