Answer:
[tex]x_1= 6, x_2=5[/tex]
Step-by-step explanation:
Well well well, let's write it down as an equation
[tex]2x^2-x+55 = (x+5)^2[/tex]
And then let's just do what's asking us to do
[tex]2x^2-x+55 = x^2+10x+25\\x^2-11x+30=0[/tex]At this point, it's quadratic formula time. Let's first calculate [tex]\Delta = b^2-4ac[/tex] to simplify the process
[tex]\Delta = 121-4(1)(30) = 121-120=1[/tex]
[tex]x= \frac{11\pm1}{2}; x_1= 6, x_2=5[/tex]
